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EXERCISE 1.2 · Q93

Q.Differentiate the following w.r.t. xx: sin⁡−14x+121+24x\sin^{-1}\dfrac{4^{x+\frac12}}{1+2^{4x}}

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First simplify: 4x+1/2=4x⋅41/2=2⋅4x4^{x+1/2}=4^x\cdot4^{1/2}=2\cdot4^x, and 24x=(22x)2=(4x)22^{4x}=(2^{2x})^2=(4^x)^2. Let t=4xt=4^x, so the argument is 2t1+t2\dfrac{2t}{1+t^2}. Put t=tan⁡θt=\tan\theta: 2tan⁡θ1+tan⁡2θ=sin⁡2θ\dfrac{2\tan\theta}{1+\tan^2\theta}=\sin2\theta. So y=sin⁡−1(sin⁡2θ)=2θ=2tan⁡−1(4x)y=\sin^{-1}(\sin2\theta)=2\theta=2\tan^{-1}(4^x). Differentiating, $\d …

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