Q.Calculate the modulation index if sinusoidal wave of peak value 4V is used to modulate the carrier of peak value of 5V.
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Concept understanding — AM Modulation Index
The modulation index (or modulation factor, or depth of modulation) tells us how strongly the message controls the carrier amplitude. For AM it is the ratio of peak modulating voltage to peak carrier voltage:
ma=VCVm
and it is often quoted as a percentage, M=(Vm/VC)×100. For distortion-free modulation Vm must be less than VC, so ma lies between 0 and 1, with a maximum permitted value of 1.0 (100% modulation). If Vm>VC then ma>1, giving over-modulation: the negative peaks are clipped, the envelope no longer matches the message, and distortion known as splattering appears.
When an AM wave is displayed on an oscilloscope, the index is read directly from the largest and smallest envelope amplitudes:
Vmax=VC(1+ma),Vmin=VC(1−ma)
which rearrange to the standard working formula
ma=Vmax+VminVmax−Vmin
The same relation holds with antenna currents, ma=(Imax−Imin)/(Imax+Imin).
When several sinusoidal signals of different frequencies modulate the carrier at once, their indices combine as the root of the sum of squares, mt=m12+m22+⋯+mn2, and this total should still not exceed unity. Because it fixes both the quality and the strength of the transmitted signal, the modulation index is one of the most important quantities in the whole study of AM.
For amplitude modulation the modulation index is the ratio of the peak amplitude of the modulating signal to the peak amplitude of the carrier.
[!ANSWER]
ma=VcVm=54=0.8
[!TLDR]
The AM modulation index is Vm/Vc=4/5=0.8.
The depth (index) of amplitude modulation measures how strongly the modulating signal controls the carrier amplitude, and is defined as
ma=VcVm
where Vm is the peak modulating voltage and Vc the peak carrier voltage. With Vm=4V and Vc=5V,
ma=54=0.8
Since ma<1, the wave is under-modulated and free of the distortion that occurs when the index exceeds unity.