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Exercise Problems · Q1

Q.Calculate the modulation index if sinusoidal wave of peak value 4V is used to modulate the carrier of peak value of 5V.

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[!TLDR]

The AM modulation index is Vm/Vc=4/5=0.8V_m/V_c = 4/5 = 0.8.

The depth (index) of amplitude modulation measures how strongly the modulating signal controls the carrier amplitude, and is defined as

ma=VmVcm_a = \dfrac{V_m}{V_c}

where VmV_m is the peak modulating voltage and VcV_c the peak carrier voltage. With Vm=4 VV_m = 4\ \text{V} and Vc=5 VV_c = 5\ \text{V},

ma=45=0.8m_a = \dfrac{4}{5} = 0.8

Since ma<1m_a < 1, the wave is under-modulated and free of the distortion that occurs when the index exceeds unity.

[!ANSWER]

ma=0.8m_a = 0.8

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