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Q.Explain amplitude modulation. Derive the voltage equation of an AM wave.

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[!TLDR]

AM varies the carrier amplitude with the message; its voltage equation eAM=Ec(1+macos⁡ωmt)cos⁡ωcte_{AM}=E_c(1+m_a\cos\omega_m t)\cos\omega_c t expands into a carrier plus upper and lower side bands.

What is amplitude modulation: Amplitude modulation (AM) is the process in which the amplitude of the carrier wave is varied in accordance with the instantaneous amplitude of the modulating (message) signal, keeping the carrier frequency and phase unchanged. The shape traced by the varying peaks of the carrier is called the envelope, and it has the same form as the modulating signal.

Derivation of the voltage equation:

Let the carrier voltage be

ec=Eccos⁡ωct,e_c = E_c\cos\omega_c t,

and the modulating voltage be

em=Emcos⁡ωmt,e_m = E_m\cos\omega_m t,

where Ec,EmE_c, E_m are peak amplitudes, ωc=2πfc\omega_c = 2\pi f_c, ωm=2πfm\omega_m = 2\pi f_m and fc≫fmf_c \gg f_m.

In AM the instantaneous amplitude of the carrier becomes

A=Ec+em=Ec+Emcos⁡ωmt=Ec ⁣(1+EmEccos⁡ωmt).A = E_c + e_m = E_c + E_m\cos\omega_m t = E_c\!\left(1+\frac{E_m}{E_c}\cos\omega_m t\right).

With the modulation index ma=Em/Ecm_a = E_m/E_c,

A=Ec(1+macos⁡ωmt).A = E_c(1+m_a\cos\omega_m t).

The AM wave is this amplitude multiplying the carrier:

eAM=Acos⁡ωct=Ec(1+macos⁡ωmt)cos⁡ωct.e_{AM} = A\cos\omega_c t = E_c(1+m_a\cos\omega_m t)\cos\omega_c t.

Expanding and using cos⁡Acos⁡B=12[cos⁡(A+B)+cos⁡(A−B)]\cos A\cos B = \tfrac{1}{2}[\cos(A+B)+\cos(A-B)]:

eAM=Eccos⁡ωct+maEc2cos⁡(ωc+ωm)t+maEc2cos⁡(ωc−ωm)t.e_{AM} = E_c\cos\omega_c t + \frac{m_aE_c}{2}\cos(\omega_c+\omega_m)t + \frac{m_aE_c}{2}\cos(\omega_c-\omega_m)t.

Interpretation: The AM wave has three components:

  • the carrier of frequency fcf_c and amplitude EcE_c,
  • the upper side band (USB) of frequency fc+fmf_c+f_m and amplitude maEc/2m_aE_c/2,
  • the lower side band (LSB) of frequency fc−fmf_c-f_m and amplitude maEc/2m_aE_c/2.

The bandwidth required is the difference between the highest and lowest frequencies present:

BW=(fc+fm)−(fc−fm)=2fm.BW = (f_c+f_m)-(f_c-f_m) = 2f_m.

The modulation index mam_a must not exceed 1; if ma>1m_a>1 the envelope is distorted (over-modulation).

[!ANSWER]

The AM voltage equation is eAM=Ec(1+macos⁡ωmt)cos⁡ωct=Eccos⁡ωct+maEc2cos⁡(ωc+ωm)t+maEc2cos⁡(ωc−ωm)te_{AM}=E_c(1+m_a\cos\omega_m t)\cos\omega_c t = E_c\cos\omega_c t + \dfrac{m_aE_c}{2}\cos(\omega_c+\omega_m)t + \dfrac{m_aE_c}{2}\cos(\omega_c-\omega_m)t; it contains the carrier at fcf_c and two side bands at fc±fmf_c\pm f_m, giving a bandwidth of 2fm2f_m.

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