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Exercise Problems · Q22

Q.A frequency modulated signal is given by 75sin[2π×90×10⁶t+6sin200πt] Determine

(a) the modulating signal frequency
(b) the carrier frequency
(c) frequency deviation
(d) the modulation index.
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[!TLDR]

Comparing with the standard FM form gives fm=100 Hzf_m = 100\ \text{Hz}, fc=90 MHzf_c = 90\ \text{MHz}, mf=6m_f = 6 and Δf=600 Hz\Delta f = 600\ \text{Hz}.

Compare 75sin⁡[2π×90×106t+6sin⁡(200πt)]75\sin[2\pi\times90\times10^{6}t + 6\sin(200\pi t)] with v=Vcsin⁡(ωct+mfsin⁡ωmt)v = V_c\sin(\omega_c t + m_f\sin\omega_m t).

  1. The inner modulating term is 200πt=2πfmt200\pi t = 2\pi f_m t, so fm=200π2π=100 Hzf_m = \dfrac{200\pi}{2\pi} = 100\ \text{Hz}.
  2. The carrier term is 2π×90×106t2\pi\times90\times10^{6}t, so fc=90×106=90 MHzf_c = 90\times10^{6} = 90\ \text{MHz}. …

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