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Exercise Problems · Q25

Q.A superheterodyne receiver using an intermediate frequency of 455 kHz is receiving a modulated signal of 910 kHz. What is the frequency of local oscillator? What could be its image frequency?

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[!TLDR]

The local oscillator is tuned to 910+455=1365 kHz910+455 = 1365\ \text{kHz}, and the image frequency is 910+2(455)=1820 kHz910+2(455) = 1820\ \text{kHz}.

In a superheterodyne receiver the local oscillator normally tracks one intermediate frequency above the incoming signal (high-side injection):

fLO=fs+fIF=910+455=1365 kHzf_{LO} = f_s + f_{IF} = 910 + 455 = 1365\ \text{kHz} …

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