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Solved Examples · Example 14

Q.RMS value of a RF voltage after amplitude modulation to a depth of 60% by a sinusoidal voltage is 50 V. Calculate the rms value of modulated voltage when modulated to depth of 80%.

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[!TLDR]

From the 60% data, VC=50/1+0.62/2=46.03V_C = 50/\sqrt{1 + 0.6^2/2} = 46.03 V; at 80% depth, VT=46.031+0.82/2=52.88V_T = 46.03\sqrt{1 + 0.8^2/2} = 52.88 V.

The rms value of a modulated RF voltage is larger than the carrier rms voltage because the sidebands add power. Since PT/PC=(VT/VC)2=1+ma2/2P_T/P_C = (V_T/V_C)^2 = 1 + m_a^2/2, the modulated and carrier rms voltages are related by

VT=VC1+ma22V_T = V_C\sqrt{1 + \frac{m_a^2}{2}}

The carrier voltage VCV_C is a fixed property of the transmitter, so it is first extracted from the 60%-modulation data and then used to find the modulated voltage at 80%.

Given VT=50V_T = 50 V at ma=0.60m_a = 0.60: …

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