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Exercise Problems · Q2

Q.The maximum and minimum amplitudes of a sinusoidal modulated wave are 4V and 1V. Determine the percentage modulation.

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[!TLDR]

Using the envelope extremes, ma=(4−1)/(4+1)=0.6m_a = (4-1)/(4+1) = 0.6, or 60 % modulation.

The amplitude-modulated envelope varies between a maximum Vmax=Vc+VmV_{max} = V_c + V_m and a minimum Vmin=Vc−VmV_{min} = V_c - V_m. Eliminating VcV_c and VmV_m gives the modulation index directly from these extremes:

ma=Vmax−VminVmax+Vminm_a = \dfrac{V_{max}-V_{min}}{V_{max}+V_{min}}

Substituting Vmax=4 VV_{max} = 4\ \text{V} and Vmin=1 VV_{min} = 1\ \text{V}:

ma=4−14+1=35=0.6m_a = \dfrac{4-1}{4+1} = \dfrac{3}{5} = 0.6

Expressed as a percentage, the percentage modulation is 0.6×100=60%0.6\times100 = 60\%.

[!ANSWER]

Percentage modulation =60%= 60\%

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