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Exercise Problems · Q19

Q.A 93.2 MHz carrier is frequency modulated by a 5 kHz sine wave. The resultant FM signal has a frequency deviation of 50kHz.

(a) Find the carrier swing of the FM wave.
(b) Determine the highest and lowest frequencies attained by the modulated signal.
(c) What is the modulation index of the FM wave?
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[!TLDR]

The carrier swings over 100 kHz, reaches 93.25 MHz at the top and 93.15 MHz at the bottom, and the modulation index is 10.

  1. Carrier swing is twice the frequency deviation:

    CS=2 Δf=2×50=100 kHzCS = 2\,\Delta f = 2\times50 = 100\ \text{kHz}

  2. The extreme frequencies lie one deviation above and below the carrier:

    fmax=fc+Δf=93.2 MHz+0.05 MHz=93.25 MHzf_{max} = f_c + \Delta f = 93.2\ \text{MHz} + 0.05\ \text{MHz} = 93.25\ \text{MHz}

    fmin=fc−Δf=93.2 MHz−0.05 MHz=93.15 MHzf_{min} = f_c - \Delta f = 93.2\ \text{MHz} - 0.05\ \text{MHz} = 93.15\ \text{MHz} …

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