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Question Bank (1 mark) · Q3

Q.Write the Boolean equation of XOR gate.

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[!TLDR]

Y=A⊕B=A‾B+AB‾Y = A \oplus B = \overline{A}B + A\overline{B}.

The XOR output is 1 for the two input combinations where the inputs differ: A=0, B=1 (giving the term A‾B\overline{A}B) and A=1, B=0 (giving AB‾A\overline{B}). Summing these two product terms gives the sum-of-products form of the gate, which is denoted compactly by the ⊕\oplus operator.

[!ANSWER]

Y=A⊕B=A‾B+AB‾Y = A \oplus B = \overline{A}B + A\overline{B}

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