Skip to content
Solved Examples · Example 17

Q.The textbook enters three Boolean expressions in sum-of-products (SOP) form onto their Karnaugh maps. Plot each expression on the appropriate two-, three- or four-variable K-map by placing a 1 in every cell that corresponds to a minterm present in the expression and a 0 in every remaining cell: Y=A‾B+ABY=\overline{A}B+AB (two variables); Y=ABC‾+A‾ B‾C+ABCY=AB\overline{C}+\overline{A}\,\overline{B}C+ABC (three variables); Y=A‾ B‾ C‾ D‾+A‾ B‾CD+ABCD+ABC‾DY=\overline{A}\,\overline{B}\,\overline{C}\,\overline{D}+\overline{A}\,\overline{B}CD+ABCD+AB\overline{C}D (four variables).

Karnataka PUCTextbookLongImportance★★★★★est
49% · 79/160 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

[!TLDR]

Each product term is a minterm; put a 1 in that cell and 0 everywhere else, and the K-map is plotted.

A Karnaugh map has 2n2^n cells for nn input variables, one cell per minterm, arranged in Gray-code order so neighbouring cells differ in exactly one variable. Plotting an SOP expression simply means marking a 1 in the cell of every product term that appears and a 0 in the rest.

Two variables: Y=A‾B+ABY=\overline{A}B+AB. A‾B=m1\overline{A}B=m_1 and AB=m3AB=m_3.

B‾\overline{B}BB
A‾\overline{A}01
AA01

Three variables: Y=ABC‾+A‾ B‾C+ABCY=AB\overline{C}+\overline{A}\,\overline{B}C+ABC. A‾ B‾C=m1\overline{A}\,\overline{B}C=m_1, ABC‾=m6AB\overline{C}=m_6, ABC=m7ABC=m_7.

B‾ C‾\overline{B}\,\overline{C}B‾C\overline{B}CBCBCBC‾B\overline{C}
A‾\overline{A}0100
AA0011

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.