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Solved Examples · Example 22

Q.The four-variable Karnaugh map shown has a horizontal quad of four adjacent 1s running across the A‾B\overline{A}B row (A‾BC‾ D‾\overline{A}B\overline{C}\,\overline{D}, A‾BC‾D\overline{A}B\overline{C}D, A‾BCD\overline{A}BCD, A‾BCD‾\overline{A}BC\overline{D}). Group this quad and write the simplified Boolean term.

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[!TLDR]

The horizontal quad along the A‾B\overline{A}B row eliminates CC and DD, leaving A‾B\overline{A}B.

A quad is a group of four adjacent 1s (a row, a column or a 2×22\times2 square). A quad removes the two variables that change within the group and keeps the two that stay constant.

C‾ D‾\overline{C}\,\overline{D}C‾D\overline{C}DCDCDCD‾C\overline{D}
A‾ B‾\overline{A}\,\overline{B}0100
A‾B\overline{A}B1111
ABAB0100
AB‾A\overline{B}0100

The encircled quad is the whole A‾B\overline{A}B row: A‾BC‾ D‾\overline{A}B\overline{C}\,\overline{D}, A‾BC‾D\overline{A}B\overline{C}D, A‾BCD\overline{A}BCD, A‾BCD‾\overline{A}BC\overline{D}. Here A‾\overline{A} and BB are common to all four cells, while CC and DD take every combination and cancel. Proof: …

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