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Solved Examples · Example 14

Q.Convert Y=(A+B)(A+C)Y = (A + B)(A + C) into canonical POS form

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[!TLDR]

Fill in the missing variable in each OR term of Y=(A+B)(A+C)Y = (A + B)(A + C) so every sum term holds all of A, B and C, giving the three-maxterm canonical POS.

In a canonical (standard) POS expression each OR term must contain every input variable. We use the identity XX‾=0X\overline{X} = 0: a sum term is ORed with XX‾X\overline{X} for each missing variable X and then distributed using P+QR=(P+Q)(P+R)P + QR = (P + Q)(P + R).

Term (A+B)(A + B): variable C is missing, so OR with CC‾C\overline{C}:

(A+B)+CC‾=(A+B+C)(A+B+C‾)(A + B) + C\overline{C} = (A + B + C)(A + B + \overline{C})

Term (A+C)(A + C): variable B is missing, so OR with BB‾B\overline{B}: …

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