Q.convert $(01000111)_{BCD}$ into Excess-3 code

Excess-3 code is formed by adding $0011$ (decimal 3) to each 4-bit BCD nibble; adding $0011$ to both nibbles of $(01000111)_{BCD}$ gives the Ex …

[!TLDR]

Add $0011$ to each nibble: $0100\to0111$ and $0111\to1010$, so the Excess-3 code is $0111\;1010$.

In this II PUC Electronics number-systems example, Excess-3 (XS-3) is a self-complementing BCD code obtained by adding $3$ (binary $0011$) to each decimal digit's 4-bit BCD group. Split the input into two nibbles - $0100$ (decimal 4) and $0111$ (decimal 7):

First nibble: $0100 + 0011 = 0111$ ($4 + 3 = 7$).

Second nibble: $0111 + 0011 = 1010$ ($7 + 3 = 10$). …