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Solved Examples · Example 28

Q.Using the four-variable K-map shown below, identify and eliminate the redundant group, then write the simplified Boolean equation.

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[!TLDR]

A group whose 1s are all already covered by other groups is redundant; removing it here leaves Y=BC‾ D‾+AC‾DY = B\overline{C}\,\overline{D} + A\overline{C}D.

The map

AB\CDAB\backslash CDC‾ D‾\overline{C}\,\overline{D}C‾D\overline{C}DCDCDCD‾C\overline{D}
A‾ B‾\overline{A}\,\overline{B}0000
A‾B\overline{A}B1000
ABAB1100
AB‾A\overline{B}0100

Redundant groups

A redundant group is a group in which every 1 is already overlapped (covered) by other groups. It contributes nothing new and must be eliminated before writing the simplified equation.

  • Vertical pair 1 (column C‾ D‾\overline{C}\,\overline{D}, rows A‾B\overline{A}B and ABAB): AA changes; constants B=1, C=0, D=0B=1,\ C=0,\ D=0 give BC‾ D‾B\overline{C}\,\overline{D}. …

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