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Question Bank (5 marks) · Q14

Q.Simplify the Boolean expression Y= Σm(1,3,5,6,8,9,11,12)+Σd(0,7,14)\Sigma m(1,3,5,6,8,9,11,12)+\Sigma d(0,7,14) using K-map.

Karnataka PUCTextbookNumeric· 5mImportance★★★★★est
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[!TLDR]

K-map grouping gives Y=A‾D+B‾D+AC‾ D‾+A‾BCY=\overline{A}D+\overline{B}D+A\overline{C}\,\overline{D}+\overline{A}BC.

Step 1 — plot the map (variables A, B, C, D; weights 8 4 2 1). Ones at 1, 3, 5, 6, 8, 9, 11, 12 and don't-cares (X) at 0, 7, 14. (Zeros lie at 2, 4, 10, 13, 15.)

Step 2 — loop the groups:

  • Quad (1, 3, 5, 7): A=0,D=1A=0, D=1 (7 is a don't-care) → term A‾D\overline{A}D.
  • Quad (1, 3, 9, 11): B=0,D=1B=0, D=1 → term B‾D\overline{B}D.
  • Pair (8, 12): A=1,C=0,D=0A=1, C=0, D=0 → term AC‾ D‾A\overline{C}\,\overline{D}.
  • Pair (6, 7): A=0,B=1,C=1A=0, B=1, C=1 (7 is a don't-care) → term A‾BC\overline{A}BC. …

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