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Question Bank (5 marks) · Q13

Q.Simplify the Boolean expression Y= Σm(0,2,6,8,10,12,14)+Σd(4,9,13)\Sigma m(0,2,6,8,10,12,14)+\Sigma d(4,9,13) using K-map. Draw the NAND gate equivalent circuit to realize the simplified equation.

Karnataka PUCTextbookNumeric· 5mImportance★★★★★est
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[!TLDR]

Every required minterm has D=0D=0, so the K-map gives simply Y=D‾Y=\overline{D}.

Step 1 — plot the map (variables A, B, C, D; weights 8 4 2 1). Ones at 0, 2, 6, 8, 10, 12, 14 and don't-cares (X) at 4, 9, 13.

Step 2 — loop the group: All seven required minterms are even numbers, so each has D=0D=0. The eight cells with D=0D=0 are 0, 2, 4, 6, 8, 10, 12, 14; of these, 0, 2, 6, 8, 10, 12, 14 are ones and 4 is a don't-care taken as 1. They form one complete octet that eliminates three variables (A, B, C) and gives the term D‾\overline{D}. The don't-cares 9 and 13 (which have D=1D=1) are left unused.

Step 3 — simplified expression: Y=D‾Y = \overline{D}. …

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